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What is the radius of the path of an electron (mass 9×10^-31 kg and charge 1.6×10^-19) moving at a speed of 3×10^7 m/s in a magnetic field of 6×10^-4 T perpendicukar to it? What is the frequency? Calculate its enegy in keV. (1 keV=1.6×10^-19 J). |
| Answer» What is the radius of the path of an electron (mass 9×10^-31 kg and charge 1.6×10^-19) moving at a speed of 3×10^7 m/s in a magnetic field of 6×10^-4 T perpendicukar to it? What is the frequency? Calculate its enegy in keV. (1 keV=1.6×10^-19 J). | |