1.

What is the principal if you earn $300 in interest at a rate of 5% for 6 years?

Answer»

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Principal=\$ 1000}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

\green{\underline \bold{<klux>GIVEN</klux> :}} \\  \tt: \implies Simple \: interest(S.I) = \$ 300 \\  \\ \tt: \implies Rate\%(r) = 5\% \\  \\  \tt: \implies Time(t) = 6 \: years \\  \\ \red{\underline \bold{To \: Find :}} \\  \tt:  \implies Principal(p) =?

ACCORDING to given QUESTION :

\tt\circ\:Let\:principal\:be\:x \\\\\bold{As \: we \: know \: that} \\  \tt:  \implies S.I=  \frac{p \times r \times t}{100}  \\  \\ \tt:  \implies 300 =  \frac{x \times 5 \times 6}{100}  \\  \\ \tt:  \implies 300 \times 100 = 30 \times x \\  \\ \tt:  \implies x =  \frac{30000}{30}  \\  \\  \green{\tt:  \implies x = \$ 1000} \\  \\  \green{\tt \therefore  Principal \: is \:\$ 1000} \\  \\  \bold{ \blue{Some \: related \: formula}} \\  \orange{ \tt \circ \: A =p(1 +   \frac{r}{100} )^{t} } \\  \\ \orange{ \tt \circ \: A=p(1 +   \frac{ \frac{r}{2} }{100} )^{2t} } \\  \\ \orange{ \tt \circ \: A =p(1 +   \frac{ \frac{r}{4} }{100} )^{4t} }



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