What is the phase difference the velocity and acceleration of a partic

1.	What is the phase difference the velocity and acceleration of a particle executing SHM?
Answer» `pi` `0.707pi` ZERO `0.5pi` Solution :Displacement of SHO `y= A sin omega t` INSTANTANEOUS velocity `v= (DY)/(dt)= A omega cos omega t` `=A omega sin(omega t +(pi)/(2))` and instantaneous acceleration `a= (DV)/(dt)= -omega^(2)y = -omega^(2) [A sin omega t]` `therefore a= A omega^(2) sin (omega t+pi)`. Hence, phase difference between instantaneous velocity and acceleration. `=\|(pi)/(2)-pi\|=\|-(pi)/(2)\|=0.5pi`.

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