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| 1. |
What is the ph of resulting solution when75 ml of 0.2m hcl and 50 ml of 0.1 m naoh mixed? |
| Answer» M1V1 - M2V2 =MV30.2×50–0.1×50=M(100)M=[H+]=0.05pH=-log[H+]pH=-log(0.05)pH=1.30103Hope You GOT It. | |