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What is the perimeter of a triangle having hypotenuse 17 cm and the length of a leg as 8 cm? *​

Answer»

using \: \: the \: \: formulas \: \\ \: p = a \: + \: b \: + \sqrt{ {a}^{2} \: + {b}^{2} } \\ \\ c \: = \: \sqrt{ {a}^{2} \: + \: {b}^{2} } \\ \\ p \: = a \: + \sqrt{ {c }^{2} \: - {a}^{2} } \: + \sqrt{ {c }^{2} } \\ \\ = \: 8 \: + \sqrt{ {17}^{2} \: - {8}^{2} } \: + \sqrt{ {17}^{2} } \\ \\ = 40 \: cm \\ \\ the \: \: perimeter \: of \: the \: \\ triangle= 40 \: cm

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