1.

What is the oxidation state of vanadium in the compound NH4vo3 a.-1;b.+1;c.+3;d.+5​

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Answer:it is +5

Explanation:as the amonium(NH4)s OXIDATION state is constant and equals to +1 so VO3 should be -1. And O 's is -2

3x-2 is -6 so to REACH -1 ,V should have an oxidation state of +5



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