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What is the oxidation state of vanadium in the compound NH4vo3 a.-1;b.+1;c.+3;d.+5 |
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Answer» Answer:it is +5 Explanation:as the amonium(NH4)s OXIDATION state is constant and equals to +1 so VO3 should be -1. And O 's is -2 3x-2 is -6 so to REACH -1 ,V should have an oxidation state of +5 |
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