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What is the oxidation state of Cr in Cr2O7²- |
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Answer» Oxygen is more electronegative than chromium, so it'll take its usual −2 charge here. There are seven oxygen atoms, so the total charge is −2⋅7=−14. Let x be the oxidation number of two chromium atoms. So, we got: x+(−14)=−2 x−14=−2 x=12 So, two chromium atoms have a total oxidation number of +12. Since one is not more electronegative than the other, we can divide the number by two to get one chromium's oxidation number. So, a chromium atom here has an oxidation number of +6. |
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