What is the number of revolutions of electron in second Bohr's orbit o

1.	What is the number of revolutions of electron in second Bohr's orbit of H atom in one second
Answer» Frequency = 1Time period1Time period Time period = TOTAL distance coveredVelocity=2πrvTotal distance coveredVelocity=2πrv Frequency = v2πrv2πr The velocity (V2)(v2) and RADIUS (r2)(r2) of the 2nd2nd Bohr's orbit : rn=(0.53×10−10n2/z)mrn=(0.53×10−10n2/z)m r2=(0.53×10−10(22)m=2.12×10−100mr2=(0.53×10−10(22)m=2.12×10−100m vn=2.165×106(z/n)m/svn=2.165×106(z/n)m/s v2=2.165×106(1/2)=1.082×106m/sv2=2.165×106(1/2)=1.082×106m/s Frequency=v22πr2=1.082×1062(π)(2.12×10−10)v22πr2=1.082×1062(π)(2.12×10−10) v=8.13×1016Hz

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