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What is the molecular weight of a gas whose density `40^(@)C and 785 mm` of `Hg` pressure is `1.3 g L^(-1)`?A. `32`B. `40`C. `15`D. `98` |
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Answer» Correct Answer - A We know that `PV=nRT` `PV=(omega)/(M)RT or P=(omega)/(V)xx(1)/(M)RT` Or `P=(d)/(M)RT` Now, `(785)/(760)=(1.3)/(M)xx0.0821xx313` or `M= 32.4 or 32` |
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