1.

What is the mole percentage of O₂ in a mixture of 7g of N₂ and 8g of O₂

Answer» MOLAR MASS of O₂ = 32g
8g of O₂  = 8/32 MOLES = 0.25 MOLE
molar mass of N₂ = 28g
7g of O₂  = 7/28 moles = 0.25 mole

mole\ percentage\ of\ O_2 = \frac{moles\ of\ O_2}{moles\ of\ O_2+moles\ of\ N_2}*100 \\ \\mole\ percentage\ of\ O_2 = \frac{0.25}{0.25+0.25} *100=\boxed{50}


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