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what is the molar conductivity of Agl at zero concentration if the `^^_(0)` values of NaI, `AgNO_(3)` and `NaNO_(3)` are respectively `126.9 Omega^(-1) cm^(2) mol^(-1), 133.4 Omega^(-1) cm^(2) mol^(-1) ` and 121.5 `Omega^(-1) cm^(2) mol^(-1)` |
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Answer» Correct Answer - Cell reaction `: Ni_((s)) + C1_(2(g)) to Ni_((ag))^(2+) + 2C1_((ag))^(-)` `E_(cell)^(0) = 1.61 V` Given : `E_(C1_(2))^(0) = 1.36 V , E_(Ni_(2+)//Ni)^(0)= - 0.25 N,` `E_("Cell ")^(0)=?` `Ni_((s))|Ni^(2+) (1M) "||" C1^(-) (1M)| C1_(2(g)) (1 atm) |Pt` `((" At LHE " Ni_((s)) to Ni_((ag)^(2+) + 2e^(-)))/(" At RHE (.(1)/(2) C1_(2(g))+ e^(-) to C1^(-)_(ag))xx2))/(Ni_((s) + C1_(2(g)) ) to Ni_((ag))^(2+) + 2C1_((ag))^(-))` The standard emf is given by `E_(" Cell ) ^(0) = E_(cathode)^(0) - E_(anode)^(0)` `=E_(C1_(2)//C1^(-))^(0) -E_(Ni^(2+)//Ni)^(0)` `= 1.36 - (- 0.25)` `=1.36 + 0. 25 = 1.61 V` |
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