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What is the molality of a solution which contains 36g of glucose in 250g of water? please answer it step by step |
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Answer» Answer : The MOLALITY of solution is, 0.8 mole/KgSolution : Given,Mass of solute, glucose = 36 gMass of solvent, water = 250 gMolar mass of glucose = 180 g/moleMolality : It is defined as the NUMBER of moles of solute present in the ONE kilogram of solvent.Formula used :Molality=\frac{w_b\times 1000}{M_b\times w_a}Molality= M B ×w a w b ×1000 where,w_bw b = mass of solute, glucosew_aw a = mass of solvent, waterM_bM b = molar mass of solute, glucoseNow put all the given values in the above formula, we getMolality=\frac{36g\times 1000}{180g/mole\times 250Kg}=0.8mole/KgMolality= 180g/mole×250Kg36g×1000 =0.8mole/KgTherefore, the molality of solution is, 0.8 mole/Kg |
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