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What is the mass of sodium hydroxide present in 500ml of 1M NaOH solution |
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Answer» 500mL SOLUTION with a final concentration of .1M Na: 22.989 AMU O: 15.999 AMU H: 1.008 AMU =39.996 AMU (rounded to 40amu) 40 amu= 1 mole NaOH To make one mole NaOH solution, dissolve 40 grams NaOH in 500mL of H2O. mL to L CONVERSION: 500/1000=.5 For .5L of 0.1M solution, we need 0.1M of solute. 0.1M of solute x 40 grams/Mole= 4 grams NaOH |
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