1.

What is the mass of 56 cm³ of carbon monoxide at STP?​

Answer»

0.07gmExplanation:At STP, 1 MOLE of any gas has a VOLUME of 22.4 L.Molar mass of CO = 12 + 16 = 28 g/molTherefore,22.4 L ( 22400 cm3) is the volume of 28g CO at STP56 cm3 will be the volume of (28/22400) X 56 = 0.07 g of CO at STP.HOPE THIS HELPS YOU ¶ THANK YOU ¶PLEASE MARK AS BRAINLIEST ™®



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