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what is the magnitude of the gravitational force between the Earth and the one kg object on its surface? (mass of the earth 6 x10²⁴kg and radius of the earth is 6.4x10 m.) |
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Answer» An artificial SATELLITE revolves round the earth at a HEIGHT of 1000km. The radius of the earth is 6.38×103km. Mass of the earth =6×1024kg; G=6.67×10−11 Nm2 kg−2. Find the orbital SPEED and PERIOD of revolution of the satellite. A 7364m s−1, 6297s. B 1064m s−1, 6297s. C 9364m s−1, 9297s. D 8364m s−1, 7297s. MEDIUM ANSWER Here, h=1000 km=1000×103m=106m r=R+h=6.38×106+106=7.38×106m Orbital speed, v0=R+hGM=7.38×1066.67×10−11×6×1024=7 |
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