1.

what is the magnitude of the gravitational force between the Earth and the one kg object on its surface? (mass of the earth 6 x10²⁴kg and radius of the earth is 6.4x10 m.)​

Answer»

ANSWER:

An artificial SATELLITE revolves round the earth at a HEIGHT of 1000km. The radius of the earth is 6.38×103km. Mass of the earth =6×1024kg; G=6.67×10−11 Nm2 kg−2. Find the orbital SPEED and PERIOD of revolution of the satellite.

A

7364m s−1, 6297s.

B

1064m s−1, 6297s.

C

9364m s−1, 9297s.

D

8364m s−1, 7297s.

MEDIUM

ANSWER

Here, h=1000 km=1000×103m=106m

r=R+h=6.38×106+106=7.38×106m

Orbital speed,

v0=R+hGM=7.38×1066.67×10−11×6×1024=7



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