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What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30^@with the direction of a uniform magnetic field of0.15 T? |
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Answer» SOLUTION :ACCORDING to Ampere.s law, `F=IlBsintheta` `thereforeF/l=IBsintheta` `thereforeF/l=(8)(0.15)sin30^(@)` `thereforeF/l=0.6Nm^(-1)` |
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