1.

What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30^@with the direction of a uniform magnetic field of0.15 T?

Answer»

SOLUTION :ACCORDING to Ampere.s law,
`F=IlBsintheta`
`thereforeF/l=IBsintheta`
`thereforeF/l=(8)(0.15)sin30^(@)`
`thereforeF/l=0.6Nm^(-1)`


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