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What is the locus of z, if amplitude of z – 2 – 3i is π/4 ? |
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Answer» Let z = x + iy. Then z – 2 – 3i = (x – 2) + i (y – 3) Let θ be the amplitude of z – 2 – 3i. Then tanθ = (y-3)/(x-2) ⇒ tan π/4 = (y-3)/(x-2) [since θ=π/4 ] ⇒ 1 = (y-3)/(x-2) i.e. x – y + 1 = 0 Hence, the locus of z is a straight line. |
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