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What is the limit of sintita and costita? |
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Answer» Answer: Step-by-step explanation: Since sin(X) is always SOMEWHERE in the range of -1 and 1, we can SET g(x) equal to -1/x and h(x) equal to 1/x. We know that the limit of both -1/x and 1/x as x approaches either positive or negative INFINITY is zero, therefore the limit of sin(x)/x as x approaches either positive or negative infinity is zero. |
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