1.

What is the length of a chord which is 12 cm from the center of a circle with radius 15 cm?

Answer»

AP= BP = AB/2 = x/2

In AOP,

∠APO = 90°

By Pythagoras,

(AO)^2 = (AP)^2 + (OP)^2

(15)^2 = (x/2)^2 + (12)^2

225 = x^2/4 + 144

x^2/4 = 225 - 144

x^2 /4 = 81

x^2 = 81 ×4

x^2 = 324

x = 18 cm



Discussion

No Comment Found

Related InterviewSolutions