1.

What is the largest 4-digit number that is divisible by each of 16, 24 and 28?1. 99142. 97643. 97444. 9864

Answer» Correct Answer - Option 3 : 9744

Given:

Numbers are 16, 24 and 28

Calculation:

Smallest 5 digit number = 10000

Now, we will have to find LCM of 16, 24 and 28 by prime factorization method

16 = 2 × 2 × 2 × 2

24 = 2 × 2 × 2 × 3

28 = 2 × 2 × 7

LCM = 2 × 2 × 2 × 2 × 3 × 7

⇒ 336

Now, after dividing 10000 by 336

10000 = 336 × 29 + 256

Required number = 10000 – 256

⇒ 9744

∴ The required number is 9744



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