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What is the largest 4-digit number that is divisible by each of 16, 24 and 28?1. 99142. 97643. 97444. 9864 |
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Answer» Correct Answer - Option 3 : 9744 Given: Numbers are 16, 24 and 28 Calculation: Smallest 5 digit number = 10000 Now, we will have to find LCM of 16, 24 and 28 by prime factorization method 16 = 2 × 2 × 2 × 2 24 = 2 × 2 × 2 × 3 28 = 2 × 2 × 7 LCM = 2 × 2 × 2 × 2 × 3 × 7 ⇒ 336 Now, after dividing 10000 by 336 10000 = 336 × 29 + 256 Required number = 10000 – 256 ⇒ 9744 ∴ The required number is 9744 |
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