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What is the integretion of sin²x.sinx dx? |
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Answer» \(\int sin^2x \;sin\,x \,dx\) \(= \int (1 -cos^2x)sin\,x\, dx\) \(= \int sin \,x\,dx - \int cos^2 x\; sin x \,dx\) \(= -cos\, x + \frac{cos^3x}{3} +C\) (By taking cos x = t ⇒ -sin x dx = dt) |
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