What is the heat of formation of liquid methyl alcohol in kJ mol−1 , use the following data. Heat of vaporization of liquid methyl alcohol = 38 kJ mol−1 . Heat of formation of gaseous atoms from the elements in their standard states: H=218 kJ mol−1,C=715 kJ mol−1, O=249 kJ mol−1 Average bond energies : C−H=415 kJ mol−1 C−O=356 kJ mol−1 O−H=463 kJ mol−1

What is the heat of formation of liquid methyl alcohol in kJ mol−1

1.	What is the heat of formation of liquid methyl alcohol in kJ mol−1 , use the following data. Heat of vaporization of liquid methyl alcohol = 38 kJ mol−1 . Heat of formation of gaseous atoms from the elements in their standard states: H=218 kJ mol−1,C=715 kJ mol−1, O=249 kJ mol−1 Average bond energies : C−H=415 kJ mol−1 C−O=356 kJ mol−1 O−H=463 kJ mol−1
Answer» What is the heat of formation of liquid methyl alcohol in $k J m o l^{- 1},$ use the following data. Heat of vaporization of liquid methyl alcohol = $38 k J m o l^{- 1}$ . Heat of formation of gaseous atoms from the elements in their standard states: $H = 218 k J m o l^{- 1}, C = 715 k J m o l^{- 1}, O = 249 k J m o l^{- 1}$ Average bond energies : $C - H = 415 k J m o l^{- 1} C - O = 356 k J m o l^{- 1} O - H = 463 k J m o l^{- 1}$