What is the excess of pressure inside the spherical drop of water of radius 1 mm. Surface tension of water is 70xx10^(-3)N//m.

What is the excess of pressure inside the spherical drop of water of r

1.	What is the excess of pressure inside the spherical drop of water of radius 1 mm. Surface tension of water is 70xx10^(-3)N//m.
Answer» Solution :Radius of water drops `r=1mm=1xx10^(-3)m` Surface tension of water `S=70xx10^(-3)Nm^(-1)` Excess PRESSURE INSIDE the DROP `P=(2S)/r=(2xx70xx10^(-3))/(1xx10^(-3))=140Nm^(-2)`