What is the equation of the line perpendicular to the line 2x + 3y= -6

1.	What is the equation of the line perpendicular to the line 2x + 3y= -6 and having y-intercept 3?
Answer» Answer: 2y = 3x + 6 Step-by-step explanation: Slope of line 2X + 3y = -6 is -2/3 (m') Let slope of other line be m" If two lines are parallel, then the PRODUCT of their SLOPES is -1 m'm"= -1 -2/3 .m" = -1 m" = 3/2 One point on this line is given, i.e., (0,3) So, by Slope intercept form y-y' = m"(x-x') y-3 = 3/2 . (x-0) 2y - 6 = 3x 2y = 3x + 6 HOPE IT WILL HELP YOU!!! HOPE IT WILL HELP YOU!!!PLEASE DO NOT FORGET TO MARK THIS ANSWER AS BRAINLIEST [For further QUESTIONING, you can follow me.]

What is the equation of the line perpendicular to the line 2x + 3y= -6 and having y-intercept 3?

Answer»

Answer:

2y = 3x + 6

Step-by-step explanation:

Slope of line 2X + 3y = -6 is -2/3 (m')

Let slope of other line be m"

If two lines are parallel, then the PRODUCT of their SLOPES is -1

m'm"= -1

-2/3 .m" = -1

m" = 3/2

One point on this line is given, i.e., (0,3)

So, by Slope intercept form

y-y' = m"(x-x')

y-3 = 3/2 . (x-0)

2y - 6 = 3x

2y = 3x + 6

HOPE IT WILL HELP YOU!!!

HOPE IT WILL HELP YOU!!!PLEASE DO NOT FORGET TO MARK THIS ANSWER AS BRAINLIEST

[For further QUESTIONING, you can follow me.]

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