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What is the equation of the circle with center (-2,5) and radius √3 |
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Answer» x^2 + y^2 + 4x - 10y + 26 = 0 Step-by-step explanation: ( x , y ) be any point of the the circle. Equation of the circle is : ⇒ √[ { x - ( - 2 ) }^2 + { y - 5 }^2 ] = √3 ⇒ ( x + 2 )^2 + ( y - 5 )^2 = ( √3 )^2 ⇒ x^2 + 2^2 + 2( 2 )( x ) + y^2 + 5^2 - 2( 5 )( y ) = 3 ⇒ x^2 + 4 + 4x + y^2 + 25 - 10y = 3 ⇒ x^2 + y^2 + 4x - 10y + 29 - 3 = 0 ⇒ x^2 + y^2 + 4x - 10y + 26 = 0 Hence the required equation is x^2 + y^2 + 4x - 10y + 26 = 0 . |
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