Saved Bookmarks
| 1. |
What is the equation of a line in slope-intercept form that crosses the x-axis at 36 and is perpendicular to the line represented byy = -49x + 5 ? |
|
Answer» Given : line that crosses the x-AXIS at 36 and is perpendicular to the line represented by y = -4/9x + 5 To FIND : equation in SLOPE-intercept form Solution: slope-intercept form : y=mx+b intercept form x/a + y/b = 1 normal form ax + by + c = 0 y = -4/9x + 5 => Slope = - 4/9 Hence Slope of perpendicular line = 9/4 intersect x axis at 36 => passes through point ( 36 , 0) => y - 0 = (9/4)(x - 36) => y = (9/4)x- 81 y = (9/4)x- 81 is the required equation Learn More: CHANGE the equation 2x+3y=6 into intercept form and explain in the ... Show that the equation of the line having slope m and making x ... |
|