1.

What is the enthalpy change of the mixture if the enthalpy change of air is 10 J, enthalpy change of water vapor is 15 J, and the humidity is 40%?(a) 10 J(b) 12 J(c) 14 J(d) 16 J

Answer» Correct answer is (d) 16 J

To explain I would say: ∆H = ∆Hair + ∆Hwater(h) = 10 + 15*0.4 = 16 J.


Discussion

No Comment Found

Related InterviewSolutions