1.

What is the distance of the pointP(4,3) from the y-axis?​

Answer»

Distance of point P(4,3) from Y - AXIS will be 4 units.

The pt. is on y - axis so, its x co - ordinate will be 0. Also, we have to find distance between them. So, the distance between them will be perpendicular.

Therefore, co-ordinates of point A on y - axis A(0, 3)

d(AP)^2 = (X2 - X1)^2 + (Y2 - Y1)^2

= (4 - 0)^2 + (3 - 3)^2

= (4)^2 + 0

= 16 + 0

= 16

d(AP)^2 = 16

Therefore, d(AP) = 4 units {Taking SQUARE root on both SIDE}



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