1.

What is the distance between thepoints A (sintita-costita,0) B(0,sintita +costita)?​

Answer»

THETA is WRITTEN as A.

Answer:

Distance between ( sinA - cosA, 0 ) and ( 0 , sinA + cosA ) is √2.

Step-by-step explanation:

Using distance formula :

  • Distance between any two points A( a,B ) and B( c, d ) is given by √{ ( a - c )^2 + ( b - d )^2 } .

On the BASIS of this :

= > Distance between the given points

= > √{ ( sinA - cosA -0 )^2 + ( 0 - sinA - cosA ) }

= > √{ sinA - cosA )^2 + ( - sinA - cosA )^2 }

= > √{ sin^2 A + cos^2 A - 2sinAcosA + sin^2 A + cos^2 A + 2sinAcosA }

= > √{ 2( sin^2 A + cos^2 A ) }

= > √2( 1 )

= > √2

HENCE distance between ( sinA - cosA, 0 ) and ( 0 , sinA + cosA ) is √2.


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