What is the difference betweencompound interests for 2 yearsand 3 year

1.	What is the difference betweencompound interests for 2 yearsand 3 years for Rs. 500 at 10%rate compounded annually?1 * 1052 260.503 505.504 165.509:43 AM
Answer» <P>Step-by-step explanation: QUESTION:- What will be in the difference between compound INTEREST for 2 years and 3 years for ₹500 at 10% rate compounded annually ? • ₹105 • ₹60.5 • ₹ 505.50 • ₹165.50 Answer:- Given :- • The principal is ₹500. • The rate is 10% per annum. • The time is 2 years and 3 years. To find :- Difference between compound interest of the above amount. Process :- Compound Interest for 1st case:- P = ₹500 R (r) = 10% T (n) = 2 years $∴CI = P(1+ \frac{r}{100} {)}^{n} \\ \\ ⇒CI = 500 (1 + \frac{10}{100} {)}^{2} \\ \\ ⇒CI = 500 ( \frac{110}{100} {)}^{2} \\ \\ ⇒CI = 500× \frac{110}{100} × \frac{110}{100} \\ \\ ⇒CI = ₹605$ Compound Interest for 2nd case:- P = ₹500 R (r) = 10% T (n) = 3 years $∴ CI = P (1+ \frac{r}{100} {)}^{n} \\ \\ ⇒CI = 500 (1+ \frac{10}{100} {)}^{3} \\ \\ ⇒CI = 500 ( \frac{110}{100} {)}^{3} \\ \\ ⇒CI = 500 × \frac{110}{100} × \frac{110}{100} \times \frac{110}{100} \\ \\ ⇒CI = ₹665.5$ Difference between Interests:- = ₹( 665.5 - 605 ) = ₹ 60.5 (Ans) ──────────────────────────── Hope it helps you... #Be brainly

What is the difference betweencompound interests for 2 yearsand 3 years for Rs. 500 at 10%rate compounded annually?1 * 1052 260.503 505.504 165.509:43 AM

Answer»

<P>Step-by-step explanation:

QUESTION:-

What will be in the difference between compound INTEREST for 2 years and 3 years for ₹500 at 10% rate compounded annually ?

• ₹105

• ₹60.5

• ₹ 505.50

• ₹165.50

Answer:-

Given :-

• The principal is ₹500.

• The rate is 10% per annum.

• The time is 2 years and 3 years.

To find :-

Difference between compound interest of the above amount.

Process :-

Compound Interest for 1st case:-

P = ₹500

R (r) = 10%

T (n) = 2 years

$∴CI = P(1+ \frac{r}{100} {)}^{n} \\ \\ ⇒CI = 500 (1 + \frac{10}{100} {)}^{2} \\ \\ ⇒CI = 500 ( \frac{110}{100} {)}^{2} \\ \\ ⇒CI = 500× \frac{110}{100} × \frac{110}{100} \\ \\ ⇒CI = ₹605$

Compound Interest for 2nd case:-

P = ₹500

R (r) = 10%

T (n) = 3 years

$∴ CI = P (1+ \frac{r}{100} {)}^{n} \\ \\ ⇒CI = 500 (1+ \frac{10}{100} {)}^{3} \\ \\ ⇒CI = 500 ( \frac{110}{100} {)}^{3} \\ \\ ⇒CI = 500 × \frac{110}{100} × \frac{110}{100} \times \frac{110}{100} \\ \\ ⇒CI = ₹665.5$

Difference between Interests:-

= ₹( 665.5 - 605 )

= ₹ 60.5 (Ans)

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