What is the degree of dissociation of sodium chloride, if the molar mass determined by a cryoscopic method was found to be 31.80 \mathrm{g} \mathrm{mol}^{-1}31.80gmol −1 [

What is the degree of dissociation of sodium chloride, if the molar ma

1.	What is the degree of dissociation of sodium chloride, if the molar mass determined by a cryoscopic method was found to be 31.80 \mathrm{g} \mathrm{mol}^{-1}31.80gmol −1 [
Answer» bnormal MOLAR mass = 31.80 gm / moleTo Find:The degree of dissociation of sodium chloride (NaCl).Calculation:- Vant HOFF factor (i) is given as:Vant Hoff factor = (NORMAL molar mass) / (Abnormal molar mass)⇒ i = 58.5 / 31.80⇒ i = 1.84- For NaCl, n = 2- For dissociation, we have:Degree of dissociation = (i - 1) / (n - 1)⇒ α = (1.84 - 1) / (2 - 1)⇒ α = 0.84- Hence, the degree of dissociation of Sodium Chloride (NaCl) is 0.84.