What is the concentration of sugar (C12H22O11) in mol L-1 if its 20 g

1.	What is the concentration of sugar (C12H22O11) in mol L-1 if its 20 g are dissolved in enough water to make a final volume up to 2L?
Answer» Molar mass of sugar (C₁₂H₂₂O₁₁) = (12×12)+(1×22)+(11×16) = 342 g mol^-1 No. of moles in 20g of sugar = 20/342 = 0.0585 mole Volume of Solution = 2L (given) Molar concentration = Moles of solute/Volume of solution in L = 0.0585mol/2L = 0.0293 mol L^-1 = 0.0293 M

What is the concentration of sugar (C12H22O11) in mol L-1 if its 20 g are dissolved in enough water to make a final volume up to 2L?

Answer»

Molar mass of sugar (C₁₂H₂₂O₁₁) = (12×12)+(1×22)+(11×16) = 342 g mol^-1

No. of moles in 20g of sugar = 20/342 = 0.0585 mole

Volume of Solution = 2L (given)

Molar concentration = Moles of solute/Volume of solution in L = 0.0585mol/2L = 0.0293 mol L^-1 = 0.0293 M