What is the center of the circle with the equation (x+1)2 +(y-3)= 9?Wr – InterviewSolution

1.

What is the center of the circle with the equation (x+1)2 +(y-3)= 9?Write your answer as an ordered pair. No extra spaces.

Answer»

(x+1)^2+(y-3)^2=0so X+1=0 , x= -1y-3=0 , y= 3center= (-1,3)

( x+1)^2 + ( y-3)^2= =x+1:; x=-1; y-3=0; y=+3

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