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What is the area of triangle with side 3.5, 4.5 and 5.6

Answer»

Heron's FORMULA :

\text {<klux>AREA</klux> = }\sqrt{p(p-a)(p-b)(p-<klux>C</klux>)} \text { where } p = \dfrac{a + b + c}{2}


GIVEN that a = 3.5, b = 4.5 , c = 5.6


p = \dfrac{3.5 + 4.5 + 5.6}{2} = 6.8


\text {Area = }\sqrt{6.8(6.8-3.5)(6.8-4.5)(6.8-5.6)} = 7.87 \text { units}^2 \text { (nearest hundredth)}


Answer: Area = 7.87 units²


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