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What is the area of a quadrilateral ABCD in which AB=3cm,BC=4cm,CD=6cm,DA=5cm and diagonal AC =5cm |
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Answer» AREA of QUADRILATERAL ABCD = area of triangle ABC + area of triangle ADC
Area of triangle ABC = 3 + 4+ 5 = 6 cm^2 2 Area of triangle ADC = 5 + 5 + 6 = 8 cm ^2 2 Area of quadrilateral = 6 + 8 = 14 cm^2. HOPE IT HELPS YOU!! |
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