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What is the angular momentum of an electron in the third orbit of an atom? |
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Answer» Here n = 3; h = 6.6 x 10-34 Js Angular momentum L = \(\frac{nh}{2π}\) = \(\frac{3 \times 6.6 \times 10^{-34}}{2 \times 3.14}\) = 3.15 x 10-34 Js |
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