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What is the angle of projection at which horizontal range and maximum height are equal?​

Answer»

R]♡HEY!!!HERE'S YOUR ANSWER!!LET ANGLE OF PROJECTION IS Ø,U IS THE INTIAL VELOCITY. WE KNOW ,MAXIMUM HEIGHT = U^2 SIN^2 Ø/2GHORIZONTAL RANGE = U^2 SIN2 Ø/GACCORDING TO QUESTION,U^2 SIN Ø/2G = U^2 SIN 2Ø/G[USE, SIN 2X = 2SINX.COSX]SIN^2 Ø/2 = 2 SIN Ø. COS ØTAN Ø = 4Ø = TAN^-1(4)ANGLE OF PROJECTION = TAN^-1(4)HOPE IT HELPS UHH!!!PLZ MARK ME AS BRAINLIEST!!



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