Dear StudentKindly find the ANSWER of your asked query.Heat energy = ML+(MCV(∆T))water+(mCv(∆T))iceQ= 777000 JL = Q−(mCv(∆T))water+(mCv(∆T))icemL = 777000−1×4200×(100−(−10))−1×2100×1101=777000−462000−231000=84000 JouleHope this INFORMATION will clear your doubt about heat energy.If you have any doubt do ask on the forum our experts will help you out.
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