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What is the active mass of an ideal gas at 44.8 atm pressure and 0c temperature in mol/lit |
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Answer» 2 mol/litExplanation:active mass of gas is equal to its CONCENTRATION I.e molarityWe need to calculate n/v MOLES PER unit volumeUsing the FORMULA PV=nRT n/V = P/RTn/V = 44.8/22.4 (RT= 0.0821×273=22.4)n/V = 2 mol/lit |
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