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What is oxidation number of [Cr(H2O)2(NH3)4]???? |
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Answer» First, the charge of complex ANION is 2-. NH3 is a neutral ligand, whereas CN is 1-, O is 2- and the PEROXIDO ligand (O2) has an OXIDATION number of -2: so 2x(-1)+2x(-2)+1x(-2)=-8. Therefore, the formal oxidation number for chromium ion MUST be +6, a d0 METAL center. 1K Views · View Upvoters. |
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