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What is molarity of the resulting solution obtained mixing `2.5 L` of 0.5 M urea solution and 500 mL of 2M urea solution ?

Answer» Molarity of solution mixing : `M_(1)V_(1)+M_(2)V_(2)=M_(3)V_(3)`
`M_(3)=(M_(1)V_(1)+M_(2)V_(2))/((V_(1)+V_(2)))`
According to available data : `M_(1)-0.5 M,V_(1)=2.5L,M_(2)=2M,V_(2)=500 mL=0.5 L`
`:. M_(3)=((0.5 Mxx2.5L)+(2Mxx0.5L))/((2.5L+0.5L))=((2.25ML))/((3.0L))=0.75M`.


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