What is limiting reagent? (ii) Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction given as: CaCO3 (s) + 2HCl(aq) CaCl2 (aq) + CO2(g) + H2O(l)What mass of calcium chloride will be formed when 250 ml of 0.76 M HCl reacts with 1000 g of calcium carbonate? Name the limiting reagent.

What is limiting reagent? (ii) Calcium carbonate reacts with aqueous

1.	What is limiting reagent? (ii) Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction given as: CaCO3 (s) + 2HCl(aq) CaCl2 (aq) + CO2(g) + H2O(l)What mass of calcium chloride will be formed when 250 ml of 0.76 M HCl reacts with 1000 g of calcium carbonate? Name the limiting reagent.
Answer» TION:can be solved with two steps :1) first we will calculate the mass of HCl in 25ml of 0.75M HCl.2) Now, calculate the mass of CaCO3 by using all information available from balance chemical equation .step 1 : calculation of mass of HCl in 25 ml of 0.75M HCl .we KNOW,MOLARITY = mass of solute/volume of solution in Lmass of HCl = 0.6844 gstep 2 : calculation of mass of CaCO3 ,CaCO3 + 2HCl ------> CaCl2 + CO2 + H2Ohere we see that,2 mole of HCl reacts with 1 mole of CaCO3.so, 2 × 36.5g of HCl reacts with 100g of CaCO3.so, 73g of HCl reacts with 100g of CaCO3.so, 1G of HCl reacts with 100/73 g of CaCO3.so, 0.6844 g of HCl reacts with 100 × 0.6844/73g of CaCO3 = 68.44/73 g = 0.9375g0.9375g of CaCO3 is required to react completely with 25ml of 0.75M HCl.