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What is `K_(c )` for the following equilibrium concentration of each substance is: `[SO_(2)]=0.60 M, [O_(2)]=0.82 M` and `[SO_(3)]=1.90 M`? `2SO_(2)(g)+O_(2)(g) hArr 2SO_(3)(g)` |
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Answer» `2SO_(2)(g) +O_(2)(g) hArr 2SO_(3)(g)` `K_(c) =[[SO_(3)]^(2)]/[[SO_(2)]^(2)[O_(2)]]=((1.9M)xx(1.9m))/((0.6m)xx(0.6 M)xx(0.82 M))` `=12.229 M^(-1) =12 .229 L mol^(-1)` |
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