1.

What is equation of latus rectums of ellipse \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?(a) x=±3(b) y=±3(c) x=±2(d) y=±2This question was addressed to me in an interview for internship.This interesting question is from Conic Sections in division Conic Sections of Mathematics – Class 11

Answer»

Correct CHOICE is (a) x=±3

To ELABORATE: Comparing the equation with \((\frac{x}{a})^2+(\frac{y}{B})^2\)=1, we get a=5 and b=4.

For ELLIPSE, c^2=a^2-b^2=25-16=9 => c=3.

Equation of latus rectum x=±c i.e. x=±3.



Discussion

No Comment Found

Related InterviewSolutions