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What is effective atomic number of Fe (Z = 26) in [Fe(CN)6]4–?(A) 12 (B) 30 (C) 26 (D) 36 |
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Answer» (D) 36 In ferrocyanide ion, [Fe(CN)6]4– Fe \(\overset{-2e^-}\longrightarrow\) Fe2+ + 6CN– → [Fe(CN)6]4– Formula : for EAN = Z – X + Y Here, Z = atomic number of iron = 26. X = number of electrons lost due to oxidation of Fe to Fe2+ = 2. Y = number of electrons donated by 6CN– = 6 x 2 = 12. ∴ EAN = 26 – 2 + 12 = 36 |
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