1.

What is effective atomic number of Fe (Z = 26) in [Fe(CN)6]4–?(A) 12 (B) 30 (C) 26 (D) 36

Answer»

(D) 36

In ferrocyanide ion, [Fe(CN)6]4– 

Fe \(\overset{-2e^-}\longrightarrow\) Fe2+ + 6CN → [Fe(CN)6]4– 

Formula : for EAN = Z – X + Y

 Here, Z = atomic number of iron = 26. 

X = number of electrons lost due to oxidation of Fe to Fe2+ = 2. 

Y = number of electrons donated by 6CN = 6 x 2 = 12.

∴ EAN = 26 – 2 + 12 = 36



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