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What is eccentricity for \((\frac{x}{25})^2+(\frac{y}{16})^2\)=1?(a) 2/5(b) 3/5(c) 15(d) 5/3I got this question during an interview.The query is from Conic Sections topic in division Conic Sections of Mathematics – Class 11

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Right ANSWER is (b) 3/5

To EXPLAIN: Comparing the equation with \((\frac{X}{a})^2+(\frac{y}{b})^2\)=1, we GET a=5 and b=4.

For ellipse, c^2=a^2-b^2= 25-16=9 => c=3.

We KNOW, for ellipse c=a*e

So, e=c/a = 3/5.



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