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| 1. |
What happens when: (i) bromoethane is treated with zinc and hydrochloric acid. (ii) hydrogen is passed into 2-bromopropane in the presence of palladium. |
| Answer» LLY, when an "alkyl halide" is TREATED with "zinc" and "hydrochloric ACID", it is "reduced" to the "respective alkane". The "nascent hydrogen" formed by the "reaction" between "zinc" and "HCl acid" reduces "ETHYL chloride to ethane". (i) Ethane is formed. (ii) Propane is OBTAINED. When 2-bromopropane is reduced in presence palladium to form propane." | |