1.

What happens to the energy of simple harmonic oscillator if its (i) amplitude is doubled ? (ii) time period is doubled? Give relevant equations.

Answer»

Solution :Energy of a simple oscillator`E = 1/2 m omega^2 A^2`
(i) When amplitude is DOUBLED energy of simple harmonic oscillator INCREASES by four times.
(ii) if time period T is doubled then ANGULAR VELOCITY `omega` is reduced to half `omega = (2pi)/(T)`
So energy of simple harmonic oscillator decreases to `1/4` of initial value.


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