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What happens to halide radical in anti markonikov mechanism?

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Answer:

Electrophilic addition OCCURS when an alkene is added with a HX, where X is a halide.

So in a carbon CHAIN, preferably propene, the double bond will first induce a +ve CHARGE on to the hydrogen from HX. Hence X now has a -ve charge.

So the double bond breaks and the hydrogen and X halide bond to the carbon chain.

Markovnikov's rule helps here by explaining where the H+ and X- ION fix themselves and hence stating the major products of the reactions.

During the formation of the intermediate, there is a carbocation. Depending on the stability of this carbocation, the position of the X- halide will vary. Hence resulting in either eg. 1-bromopropane or 2-bromopropane.

Explanation:

Hope this will help u

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