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What e.m.f. will be induced in a 10 inductor in which current changes from 10 A to 7 A in `9xx10^(-2) s` ? |
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Answer» Here, `e = ?, L = 10 H, I_(1) = 10 A, I_(2) = 7 A, dt = 9 xx 10^(-2) s` As `e = (L dl)/(dt) = (-L(I_(2)-I_(1)))/(dt) = (-10(7 - 10))/(9 xx 10^(-2)) = 333.3` volt. |
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